-1,5x^2+x+4=0

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Solution for -1,5x^2+x+4=0 equation:



-1.5x^2+x+4=0
a = -1.5; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·(-1.5)·4
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*-1.5}=\frac{-6}{-3} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*-1.5}=\frac{4}{-3} =-1+1/3 $

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